If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4k^2+32k+60=0
a = 4; b = 32; c = +60;
Δ = b2-4ac
Δ = 322-4·4·60
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-8}{2*4}=\frac{-40}{8} =-5 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+8}{2*4}=\frac{-24}{8} =-3 $
| 45.60+0.10=b | | 6+7=p*9 | | 12=10+6x | | 4^(2x)=12 | | 8y=126 | | 1/2m-2=3 | | 2=161-t | | 21s-5=37 | | 7x+1=108.3 | | y/4-19=-16 | | t/7+1=-1 | | √x=9 | | √x^2=81 | | (4x*4*4-5x*5*5*5+x+8)-(3x*3*3*3-4x+9=6x*6) | | j/2-4=2 | | k/2+16=20 | | 22=155-q | | q/3-1=5 | | q/4+11=6 | | 106-2y=108 | | g/9-14=-13 | | 8(3.14)=3.14(x)^2(6) | | 16/3=11/3+y | | 2m^2+10m-28=0 | | 2112212m+56472-4578m=21 | | (7+x)(5x+9)=0 | | 2m^2+10m+7=0 | | 2x+10=85-x | | 5/3w-2=7 | | R=-2t^+87t+90 | | -8=1/4y-3 | | 5+1/2h=2 |